Page:Sewell Dikshit The Indian Calendar (1896) proc.djvu/98

1667 − 1665 = 2 = 9 m. after 13 h. 6 m. = 13 h. 15 m.

	a.	b.	c.
Again for sunrise (as before)	1335	943	439
For 13 hours (Table V.)	183	20	1
For 15 minutes (Do.)	4	0	0
	1522	963	440
Equation for (${\displaystyle b}$) (963) (Table VI.)	108
Equation forDo. (${\displaystyle c}$) (440) (Table VII.)	38
	1668	${\displaystyle =t}$.

1668 − 1667 = 1 = 4 m. before 13 h. 15 m. = 13 h. 11 m.

	a.	b.	c.
Again for sunrise (as before)	1335	943	439
For 13 hours (Table V.)	183	20	1
For 11 minutes (Do.)	3	0	0
	1521	963	440
Equation for (${\displaystyle b}$) (963) (Table VI.)	108
Equation forDo. (${\displaystyle c}$) (440) (Table VII.)	38
Actual end of the tithi	1667	${\displaystyle =t}$.

Thus 13 h. 11 m. after sunrise is the absolutely accurate ending time of the tithi.

(c) The beginning of the tithi, Jyeshṭha śuk. 5. Now for the beginning. 1463 (the original ${\displaystyle t}$. as found) − 1333 (beginning of the tithi, (Table VIII.) = 130 = (Table X.) (7 h. 5 m. + 2 h. 8 m.) = 9 h. 13 m.; and we have this as the point of time before sunrise on Wednesday when the tithi begins.

					a.	b.	c.
For sunrise (as before)					1335	943	439
	a.	b.	c.
For 9 hours (Table V.)	127	14	1
For 13 minutes (Do.)	3	0	0
Deduct	130	14	1		130	14	1
					1205	929	438
Equation for (${\displaystyle b}$) (929) (Table VI.)					79
Equation forDo. (${\displaystyle c}$) (438) (Table VII.)					37
					1667	${\displaystyle =t}$.

(The beginning of the tithi) 1333 − 1321 = 12 = Table X.) 51 m. after the above time (9 h 13 m.), and this gives 8 h. 22 m. before sunrise. We proceed again.

	a.	b.	c.
For 9 h. 13 m. before sunrise (found above)	1205	929	438
Plus for 51 minutes (Table V.)	12	1	0
	1217	930	438
Equation for (${\displaystyle b}$) (930) (Table VI.)	80
Equation forDo. (${\displaystyle c}$) (438) (Table VII.)	37
	1334	${\displaystyle =t}$.